Planck's constant has the dimensions (unit) of

Energy

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Linear momentum

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Work

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Angular momentum

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Solution

The correct option is D Angular momentum
[h] =[Angular~momentum]= $[M L^{2} T^{- 1}]$ (Else use the Bohr's 2nd postulate)

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Similar questions

The ratio of the dimensions of Planck constant and that of moment of inertia has the dimensions of

n

h

q

B

(\begin{matrix} \frac{n h}{2 π q B} \end{matrix})

n^{t h}

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