Plane consists of 25 straight lines, no two of them being parallel and no three of them being concurrent. Determine the number of points of intersection.

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Solution

The correct option is C
300

Plane has $25$ lines

No two of them are parallel

No three of them are concurrent

So the no .of points of intersection is given as $^{n} C_{2}$

Here $n = 25$

$⟹^{25} C_{2}$

$⟹ \frac{25!}{23! 2!}$

$⟹ \frac{25 \times 24}{2}$

$⟹ 25 \times 12 = 300$

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Plane consists of 25 straight lines, no two of them being parallel and no three of them being concurrent. Determine the number of points of intersection.

The correct option is C 300Plane has 25 lines No two of them are parallelNo three of them are concurrent So the no .of points of intersection is given as nC2Here n=25⟹25C2⟹25!23!2!⟹25×242⟹25×12=300

The correct option is C
300

Plane has $25$ lines

No two of them are parallel

No three of them are concurrent

So the no .of points of intersection is given as $^{n} C_{2}$

Here $n = 25$

$⟹^{25} C_{2}$

$⟹ \frac{25!}{23! 2!}$

$⟹ \frac{25 \times 24}{2}$

$⟹ 25 \times 12 = 300$