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Plane electro...

Question

Plane electromagnetic wave of intensity S are incident normally on a flat surface.Only a fraction $f$ of the incident energy is absorbed.What is the radiation pressure?

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Solution

Given,

Radiation intensity= $S$

Reflected radiation $= S (1 - f)$

Speed of light is $C = 3 \times 10^{8} m s^{- 1}$

Radiation pressure, $P = \frac{S}{c} + \frac{S (1 - f)}{c} = \frac{2 S}{c} - \frac{S f}{c}$

Hence, radiation pressure, $\frac{S (2 - f)}{c}$ $N m^{- 2}$

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