Question

Plane Geometry
The straight line, which is parallel to the base of a triangle, divides its area in half. In what ratio does it divide its lateral sides?

Answer 1

Let line $S$ cuts $\Delta ABC$ in $2$ halves & is $\parallel$ to $BC$, by basic proportionality theorem.

$\frac{AD}{BD}=\frac{AE}{CE}$

So, line $S$ divide $AB$ & $AC$ in $1:1$ ratio.