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Question

Planet X has twice the mass as the earth and orbits its star as the same orbital distance that the earth orbits the sun. If Planet X takes 365 and 1/4 days to complete one orbit around its star, how does the angular momentum of Planet X compare to the angular momentum of the earth?
It can be assumed that both orbits are circular.

A
LX=2LEarth
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B
LX=LEarth2
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C
LX=LEarth
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D
LX=4LEarth
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E
LX=LEarth4
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Solution

The correct option is B LX=2LEarth
mX=2mE
rX=rE
The time period of revolution of both the planets is same.
Hence 2πrXvX=2πrEvE
vX=vE
The ratio of angular moementa=LXLE=mXvXrXmEvErE
=mXmE
=2

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