Question

Plates of area A are arranged as shown. The distance between each two plates is d, the net capacitance between ‘a’ and ‘b’ is:

• A. $\frac{{\in }_{0}A}{d}$
• B. $\frac{7{\in }_{0}A}{d}$
• C. $\frac{6{\in }_{0}A}{d}$
• D. $\frac{5{\in }_{0}A}{d}$

Answer 1

The correct option is A $\frac{{\in }_{0}A}{d}$