Question

Platinum crystallizes in a fcc lattice with a unit cell length a. The distance between nearest neighbour is? ( ans in terms of 'a')

Answer 1

Dear student,

In FCC lattice atoms are present at the corner and the faces of the cube.
The edge length of cube = a
The nearest neighbour in FCC = $\frac{edgelength}{\sqrt{2}}$
Edge length = a
The nearest neighbour are at the distance = $\frac{a}{\sqrt{2}}$

Regards