Please explain why mgh/ 1+h/R is the change in potential energy when a body is raised to height h from earth's surface

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Solution

The gravtational potential energy at a point due to an object ( if it is not in bulk of object ) is given by =
P E.= -(GMm)/r.

on raising to a height H

PE= - (GMm)/(r+H)

Change in PE = - (GMm)/(r+H) - [-(GMm)/r.)] = GMm [(1/r)-(1/r+H)] = mgh/ 1+h/R

hope you understand this

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Please explain why mgh/ 1+h/R is the change in potential energy when a body is raised to height h from earth's surface

The gravtational potential energy at a point due to an object ( if it is not in bulk of object ) is given by = P E.= -(GMm)/r. on raising to a height H PE= - (GMm)/(r+H) Change in PE = - (GMm)/(r+H) - [-(GMm)/r.)] = GMm [(1/r)-(1/r+H)] = mgh/ 1+h/R hope you understand this

The gravtational potential energy at a point due to an object ( if it is not in bulk of object ) is given by =
P E.= -(GMm)/r.

on raising to a height H

PE= - (GMm)/(r+H)

Change in PE = - (GMm)/(r+H) - [-(GMm)/r.)] = GMm [(1/r)-(1/r+H)] = mgh/ 1+h/R

hope you understand this