Please follow the Aufbau principle, Pauli exclusion principle and Hund's rule to determine the four quantum numbers (principle, angular, magnetic, spin) for the final electron of Zirconium.

4, 2, - 1, + 1 / 2

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5, 1, 0, - 1 / 2

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4, 3, - 3, - 1 / 2

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5, 0, 0, - 1 / 2

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Solution

The correct option is A $4, 2, - 1, + 1 / 2$
Zirconium has valence shell electronic configuration of $5 s^{2} 4 d^{2}$ thus last electron belongs to $4 d$ orbital.

quantum numbers for the final electron of Zirconium is
$n = 4, l = 2$ (for d-orbital), $m_{l} = - 1, m_{s} = + 1 / 2$
Hence, the correct option is A.

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Please follow the Aufbau principle, Pauli exclusion principle and Hund's rule to determine the four quantum numbers (principle, angular, magnetic, spin) for the final electron of Zirconium.

The correct option is A 4,2,−1,+1/2Zirconium has valence shell electronic configuration of 5s24d2 thus last electron belongs to 4d orbital.quantum numbers for the final electron of Zirconium isn=4,l=2 (for d-orbital), ml=−1,ms=+1/2Hence, the correct option is A.