Please see the reaction given below. If the given reaction is possible then enter 1, otherwise enter 0 if the reaction cannot happen.
$C u O + H_{2} S O_{4} \to C u S O_{4} + H_{2} O$

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Solution

$C u O + H_{2} S O_{4} \to C u S O_{4} + H_{2} O$

It is a double displacement reaction, in which hydrogen is more reactive than copper and hence it can displace copper from its compound. Therefore, this reaction is possible and the products formed will be copper sulfate and water respectively.

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Similar questions

Calculate the mass of copper(II) oxide required when reacts with excess sulfuric acid to form 1 mol of $C u S O_{4}$ . The equation for the reaction is:

$C u O + H_{2} S O_{4} \to C u S O_{4} + H_{2} O$

[Given $: C u = 63.5; O = 16; S = 32$ ]

Q. Given a reaction:

{C r}_{2} O_{7}^{2 -} + {F e}^{2 +} + H^{\oplus} ⟶ {C r}^{3 +} + {F e}^{3 +} + H_{2} O

The balanced equation is

6 {F e}^{2 +} + 14 H^{\oplus} + {C r}_{2} O_{7}^{2 -} ⟶ 6 {F e}^{3 +} + 2 {C r}^{3 +} + 7 H_{2} O

.
If true enter 1, else enter 0.

C_{2} H_{2} N a N H_{2} - ---- \to C H_{3} B r - --- \to N a N H_{2} - ---- \to C_{2} H_{5} B r - ---- \to N a - --- \to N H_{3} (l)

trans-2-pentene.

If the given reaction is correct then enter 1 else enter 0.

Q. In the reaction given below, hydrogen is getting:

C u O + H_{2} \to C u + H_{2} O

Q. Complete reaction is :

T i C l_{4} + H_{2} O \to T i (O H)_{4} + 4 H C l

.
If true enter 1 else 0.

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Please see the reaction given below. If the given reaction is possible then enter 1, otherwise enter 0 if the reaction cannot happen. CuO+H2SO4→CuSO4+H2O

CuO+H2SO4→CuSO4+H2OIt is a double displacement reaction, in which hydrogen is more reactive than copper and hence it can displace copper from its compound. Therefore, this reaction is possible and the products formed will be copper sulfate and water respectively.

Please see the reaction given below. If the given reaction is possible then enter 1, otherwise enter 0 if the reaction cannot happen.
$C u O + H_{2} S O_{4} \to C u S O_{4} + H_{2} O$

$C u O + H_{2} S O_{4} \to C u S O_{4} + H_{2} O$

It is a double displacement reaction, in which hydrogen is more reactive than copper and hence it can displace copper from its compound. Therefore, this reaction is possible and the products formed will be copper sulfate and water respectively.