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Standard XII

Physics

Coulomb's Law - Mathematical Form

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Question

Plot a graph showing the variation of coulomb force $(F)$ versus $(\frac{1}{r^{2}})$ where $r$ is the distance between the two charges of each pair of charges : $(1 μ C, 2 μ C)$ and $(2 μ C, - 3 m u C)$ . Interpret the graphs obtained.

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Solution

$F = \frac{1}{4 π ϵ_{0}} \frac{q_{1} q_{2}}{r^{2}}$
The graph between $F$ and $\frac{1}{r^{2}}$ is a straight line of slope $\frac{1}{4 π ϵ_{0}} q_{1} q_{2}$ passing through origin in both the cases.
Since, magnitude of the slope is more for attention, therefore, attractive force is greater than repulsive force.

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Plot a graph showing the variation of coulomb force (F) versus (1r2) where r is the distance between the two charges of each pair of charges : (1μC,2μC) and (2μC,−3muC). Interpret the graphs obtained.

F=14πϵ0q1q2r2The graph between F and 1r2 is a straight line of slope 14πϵ0q1q2 passing through origin in both the cases.Since, magnitude of the slope is more for attention, therefore, attractive force is greater than repulsive force.

Plot a graph showing the variation of coulomb force $(F)$ versus $(\frac{1}{r^{2}})$ where $r$ is the distance between the two charges of each pair of charges : $(1 μ C, 2 μ C)$ and $(2 μ C, - 3 m u C)$ . Interpret the graphs obtained.