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Stopping Potential vs Frequency

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Question

Plot a labelled graph of $| V_{s} |$ where $V_{s}$ is stopping potential versus frequency f of the incident radiation.
State how will you use this graph to determine the value of Planck's constant.

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Solution

Let the work function of the metal be $ϕ$ .
Stopping potential $V_{s} = \frac{h f}{e} - \frac{ϕ}{e}$
Thus the graph of $| V_{s} |$ versus $f$ is a straight line having the slope $\frac{h}{e}$ as shown in the figure.
After finding the slope from the graph, we can determine the value of Plank's constant as Slope $= \frac{h}{e}$
$⟹$ $h = e \times$ Slope

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