Plot of log x/m against log P is a straight line inclined at an angle of 45∘. When the pressure is 0.5 atm and Freundlich parameter. K is 100, the amount of the solute adsorbed per gram of adsorbent will be (log 5 = 0.6990)
5 g
According to Freundlich equation, xm=KP1n
or log xm=log K+1n logP
∴ Plot of log xm vs log P is a straight line
with slope = 1n and intercept = log K. Thus,
1n = tan θ = tan 45∘ = 1 or n = 1
At P = 0.5 atm and K = 10, xm = 10 × (0.5) = 5
∴ x (i.e. amount adsorbed per gram) = 5 g.