Plot of log (x/m) against log P is a straight line inclined at an angle of 45∘. When the pressure is 0.5 atm and the proportionality constant in Freundlich's equation is 10, the amount of solute per gram of adsorbent will be:
A
1 g
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B
2 g
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C
3 g
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D
5 g
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Solution
The correct option is D 5 g According to Freundlich adsorption isotherm, xm=kP1n ⇒log(xm)=logk+1nlogP
Since it is a straight line,
Slope= tan45o=1n ⇒n=1
Given, when the pressure is 0.5 atm and Freundlich parameter is 10, So xm=10(0.5)1 ⇒xm=5g
Therefore the amount of solute per gram of adsorbent will be 5 g.