Plot the graph of y=(x−3)2+7
y=(x−3)2+7(y−7)=(x−3)2 Comparing it with (y−y1)=(x−x1)2 We get x1=3; y1=7 ∴ the parabola will have it's vertex at (3,7)
Plot the graph of y=(x-3)2+7
Plot the graph of |y|=ln(x)