Plot the points A(2, 5), B(–2, 2) and C(4, 2) on a graph paper. Join AB, BC and AC. Calculate the area of ∆ABC.

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Solution

Abscissa of D = Abscissa of A = 2
Ordinate of D = Ordinate of B = 2

Now,
BC = (2 + 4) units = 6 units
AD = (5 – 2) units = 3 units

$Area of ∆ A B C = \frac{1}{2} \times Base \times Height = \frac{1}{2} \times B C \times A D = \frac{1}{2} \times 6 \times 3 = 9$

Hence, area of ∆ABC is 9 square units.

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Plot the points A(2, 5), B(–2, 2) and C(4, 2) on a graph paper. Join AB, BC and AC. Calculate the area of ∆ABC.

Abscissa of D = Abscissa of A = 2 Ordinate of D = Ordinate of B = 2 Now, BC = (2 + 4) units = 6 units AD = (5 – 2) units = 3 units Area of ∆ABC=12×Base×Height =12×BC×AD =12×6×3 =9 Hence, area of ∆ABC is 9 square units.