Plots for 2s orbital are: X, Y and Z are respectively
A
R, R2 and 4πr2R2
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B
R2, R and 4πr2R2
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C
4πr2R2, R2 and R
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D
R2, 4πr2R2 and R
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Solution
The correct option is BR2, R and 4πr2R2 Y will be definitely 'R' because value of R cannot be negative, thus X will be R2 and Z will be 4πr2R. Z represents radial probability function; its value will be zero at origin.