Plumbous ion is represented as:

P b^{+ 2}

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P b^{+ 4}

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P b^{+ 3}

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P b^{+ 1}

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Solution

The correct option is B $P b^{+ 2}$
$P b^{2 +}$ = Plumbous ion
$P b^{4 +}$ = Plumbic ion
$∴$ The correct answer is $(A)$ .

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Similar questions

P b^{+ 4}

[1] P b^{2 +} > P b^{4}, S n^{2 +} > S n^{4 +}

[2] P b^{2 +} < P b^{4}, S n^{2 +} < S n^{4 +}

[3] P b^{2 +} > P b^{4}, S n^{2 +} < S n^{4 +}

[4] P b^{2 +} < P b^{4}, S n^{2 +} > S n^{4 +}

[5] S n^{2 +} < P b^{2 +}, S n^{4 +} > P b^{4 +}

[6] S n^{2 +} < P b^{2 +}, S n^{4 +} < P b^{4 +}

lead reacts with oxygen. which ion should we take for lead? pb+1 or pb+2 or pb+4....

Identify the monoatomic and polyatomic ions from the following equation-
$P b (N O_{3})_{2}$ + $K_{2} S O_{4}$ $\to$ $2 K N O_{3}$ + $P b S O_{4}$

P b, P b^{2 +}, a n d P b^{4 +}

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