PM and PN are the perpendiculars from any point P on the rectangular hyperbola xy=8 to the asymptotes. If the locus of the mid point of MN is a conic, then the least distance of (1,1) to director circle of the conic is
A
√3 unit
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B
√2 unit
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C
2√3 unit
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D
2√5 unit
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Solution
The correct option is B√2 unit
Here, OMPN is rectangle. P≡(2√2t,2√2t)
Mid point of MN=OP ∴(h,k)=(√2t,√2t) Thus h×k=√2t⋅√2t=2 Thus locus is the rectangular hyperbola xy=2 The director circle to this rectangular hyperbola is the point circle with center (0,0). Thus distance between (0,0) and (1,1) is √2 unit