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Relation between Inradius and Perimeter of Triangle

Point 3, 2, -...

Question

Point (3, 2), (-2, -3) and (2, 3) form a/an...........triangle.

Equilateral

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Right Angle

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Isosceles

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None of the above

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Solution

The correct option is B Right Angle
Here since
$(s l o p e) A B \times (s l o p e) B C$
$\frac{1}{- 1} \times \frac{8}{8} = - 1$
Lines AB and BC are $⊥$ so right angle triangle.

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