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Question
Point charge (q) moves from point (P) to point (S) along the path PQRS as shown in fig. in a uniform electric field E, pointing parallel to the positive direction of the x-axis. The co-ordinates of the points P,Q,R and S are (a,b,0),(2a,0,0),(a,−b,0) and (0,0,0) respectively. The work done by the field in the above process is given by the expression -
Point charge (q) moves from point (P) to point (S) along the path PQRS as shown in fig. in a uniform electric field E, pointing parallel to the positive direction of the x-axis. The co-ordinates of the points P,Q,R and S are (a,b,0),(2a,0,0),(a,−b,0) and (0,0,0) respectively. The work done by the field in the above process is given by the expression -
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Solution
The correct option is B −qEa
Work done depends upon net displacement of particle as
W=→F.→r,
Here,
→F=qE→i
→r=0^i+0^j−a^i−b→j=−a^i−b^j
W=qE^i.(−a^i−b^j)
W=−qEa
Work done depends upon net displacement of particle as
W=→F.→r,
Here,
→F=qE→i
→r=0^i+0^j−a^i−b→j=−a^i−b^j
W=qE^i.(−a^i−b^j)
W=−qEa
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