Point charges $+ q, + q, - q$ and $- q$ are placed at the corners A, B, C and D respectively of a square. O is the point of intersection of the diagonals AC and BD. The resultant electric field intensity at the point O.

Acts in a direction parallel to AB

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Acts in a direction parallel to BC

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Acts in a direction parallel to CD

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Is zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C Acts in a direction parallel to BC
The electric fields due to the four charges are shown in the figure. The fields due to A and B act along AO and BO respectively, and that due to C and D act along OC and OD respectively, such that the resultant of these four act on point O downwards, that is, parallel to side BC.

Suggest Corrections

Similar questions

Q. Charges q, 2q, 3q and 4q are placed at the corners A, B, C and D of a square as shown in the following figure. The direction of electric field at the centre of the square is parallel to side.

Q. Charges q, 2 q, 3 q and 4 q are placed at the corners A, B, C and D of a square as shown in the following figure. The direction of electric field at the center of the square is along.

Q. Point charges each of magnitude

Q

are placed at three corners of a square as shown in the diagram.
What is the direction of the resultant electric field at the fourth corner?

Four charges q, 2q, 3q and 4q are placed at corners A, B, C and D of a square as shown in the figure below. Find the direction of electric field at the centre P of the square.

Q. Charge

+ q, + q a n d + q

are placed at the corners,

A B a n d C

respectively of an equilateral triangle

A B C

. If

E

is the electric field at the circumcentre

O

of the triangle, due to the charge

+ q

, then the magnitude and direction of the resultant electric field at

O

is :

Join BYJU'S Learning Program

Point charges +q,+q,−q and −q are placed at the corners A, B, C and D respectively of a square. O is the point of intersection of the diagonals AC and BD. The resultant electric field intensity at the point O.

Point charges $+ q, + q, - q$ and $- q$ are placed at the corners A, B, C and D respectively of a square. O is the point of intersection of the diagonals AC and BD. The resultant electric field intensity at the point O.