Question

Point masses of $1,2,3$ and $10kg$ are lying at the point $(0,0)$, $(2,0)$, $(0,3)$ and $(-2,-2)$ respectively in $x-y$ plane. The moment of inertia of this system about $y-axis$ will be. (in $kg-m^2$).

Answer 1

Moment of inertia(MOI) about $y-axis$, $I=m{x}^2$

$\therefore MOI=1\times 0+2\times 2^2+3\times 0+10\times (-2{)}^2=48$ $kg-m^2$