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Quantitative Aptitude

Coordinate Geometry

Point of inte...

Question

Point of intersection of the diagonals of square is at origin and coordinate axis are drawn along the diagonals.

If the side is of length a, then one which is not the vertex of square

A

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B

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C

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D

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Solution

The correct option is A

Obviously, from right angled triangle BOA

OA = OB = $\frac{a}{\sqrt{2}}$

Hence the vertex $(a \sqrt{2}, 0)$ is not the vertex of square.

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