Point of intersection of the pair of straight lines represented by the equation $8 x^{2} + 3 y^{2} - 10 x y - 10 x + 8 y - 3 = 0$ is

(- 5, 7)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(4, 7)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(5, 7)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(- 4, 7)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(5, 7)$
On satisfying each point, say that $(5, 7)$ satisfies the given equation and this is the point of intersection of pair of lines.

Suggest Corrections

Similar questions

3 x^{2} + 10 x y + 3 y^{2} - 15 x - 21 y + 18 = 0

2 x^{2} - 10 x y + 26 y^{2} + 5 x - 16 y - 3 = 0

3 x^{2} + 10 x y + 3 y^{2} - 2 x + 2 y - 1 = 0

3 x^{2} + 10 x y + 3 y^{2} - 11 x + 7 y - 20 = 0

3 x^{2} + 10 x y + 3 y^{2} = 0

x^{2} - y^{2} = 0

8 x^{2}

3 y^{2}

3 x^{2} + 10 x y + 3 y^{2} - 15 x - 21 y + k = 0

k

Join BYJU'S Learning Program