Question

Point out the angular momentum of an electron in $3p$ orbital

• A. $0$
• B. $\frac{h}{\sqrt{2}\pi }$
• C. $\frac{2h}{\pi }$
• D. $\frac{h}{\pi }$

Answer 1

The correct option is B $\frac{h}{\sqrt{2}\pi }$

Orbital angular momentum $=\sqrt{l(l+1)}\frac{h}{2\pi }$
For $3p$ orbital, $l=1$
hence orbital Angular momentum in this case $=\sqrt{1(1+1)}\frac{h}{2\pi }$
$=\frac{h}{\sqrt{2}\pi }$