Point out the correct floral formula of cruciferae

K_{2 + 2} C_{4 x} A_{2 + 4} G_{(2)}

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K_{5} C_{6} A_{3} G_{(2)}

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K_{2 + 2} C_{4} A_{2 + 4} G_{(2)}

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K_{4} C_{4} A_{2} G_{(2)}

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Solution

The correct option is A $K_{2 + 2} C_{4} A_{2 + 4} G_{(2)}$
It is the flowers that make Brassicaceae one of our easier families to recognize. They are (usually) radially symmetric, with 4 sepals, 4 petals, 6 stamens (2 short and 4 long), and a single bilocular pistil having parietal placentation. Also, there is no other tetramerous family with 6 stamens and no other family with the combination of 2 locules and parietal placentation. The 6 stamens are also unusual in being of two lengths, 4 long and 2 short.
Thus, the correct answer is option C.

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