Point out the correct statement amongst the following.

{[C u (C N_{4})]}^{3 -}

has tetrahedral geometry and

d s p^{2}

hybridization

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{[N i (C N_{6})]}^{4 -}

is octahedral and Ni had

d^{2} s p^{3}

hybridization

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{[Z n B r_{4}]}_{4}^{2 -}

is tetrahedral and diamagnetic

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{[C r {(N H_{3})}_{6}]}_{6}^{3 +}

has octahedral geometry and

s p^{3} d^{2}

hybridization

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Solution

The correct option is C ${[Z n B r_{4}]}_{4}^{2 -}$ is tetrahedral and diamagnetic
${[C u (C N_{4})]}^{3 -}$ has tetrahedral geometry and $s p^{3}$ hybridization.
${[N i (C N_{6})]}^{4 -}$ is octahedral and Ni had $s p^{3} d^{2}$ hybridization.
${[C r {(N H_{3})}_{6}]}_{6}^{3 +}$ has octahedral geometry and $d^{2} s p^{3}$ hybridization.
${[Z n B r_{4}]}_{4}^{2 -}$ is tetrahedral and diamagnetic
$Z n^{+ 2}, d^{10} s p^{3}$ hybridization so tetrahedral geometry.
And it has zero unpaired electron so diamagnetic.

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