Point P(2,-3) lies on the line represented by the equation:
2x + y = 1
x + 2y = 0
2x + 2y = 0
x + y = 1
Consider the equation 2x + y = 1.
For x = 2 and y = -3,
LHS = 2(2) + (-3) = 4 - 3 =1 = RHS
Therefore, P(2, -3) lies on the line represented by the equation 2x + y = 1.
The area of the triangle formed by the lines, y = x, x + y = 2 and the line through p(h, k) and parallel to the x-axis is 4h2, then the point P lies on
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