Point P divides the line segment joining the points A(−1,3) and B(9,8) such that APPB=k1. If P lies on the line x−y+2=0, find the value of k.
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Solution
We know that by section formula, the co-ordinates of the points which divide internally the line segment joining the points (x1,y1) and (x2,y2) in the ratio m:n are
(x,y)=(mx2+nx1m+n,my2+ny1m+n)
According to given conditions ,let's say coordinates of point P are (x,y)
P(x,y)=P(9k−1k+1,8k+3k+1)
It is gien that point P lies on the line x−y+2=0 ,