Question

Point P lies on the line 3x+ 4y - 12 = 0. If X- coordinate of P is a, then its y-coordinate is ______.

• A. $\frac{(12-3a)}{4}$
• B. $\frac{(12-4a)}{3}$
• C. $\frac{(12+3a)}{4}$
• D. $\frac{(3a-12)}{4}$

Answer 1

The correct option is A

$\frac{(12-3a)}{4}$

The points on the line should satisfy the equation of the line.
So , the point P(a,y) satisfies the equation. Hence,
3x+ 4y - 12 = 0
3(a) + 4(y) -12 = 0
4y = 12-3a
Y = $\frac{(12-3a)}{4}$