(a) We know that every point in a line is invariant under the reflection in the same line.
Since, points (−5,0) and (4,0) lie on the x-axis.
⇒ Points (−5,0) and (4,0) are invariant under reflection in x-axis.
Given that the points (−5,0) and (4,0) are invariant on reflection in line L1.
∴ The line L1 is x-axis, whose equation is y=0
Similarly, the given points (0,−6) and (0,5) lie on the y-axis and are invariant on reflection in line L2.
∴ The line L2 is y-axis, whose equation is x=0
(b) P′= The image of P(2,6) in L1
= The image of P(2,6) in x-axis =(2,−6)
And, Q′= The image of Q(−8,−3) in L1
= The image of Q(−8,−3) in x-axis =(−8,3)
(c) P′′= The image of P(2,6) in L2
= The image of P(2,6) in y-axis =(−2,6)
Q′′= The image of Q(−8,−3) in L2
= The image of Q(−8,−3) in y-axis =(8,−3)
(d) Since, Q′=(−8,3) and Q′′=(8,−3)
and we know M0(−x,y)=(x,−y)
∴ The single transformation that maps Q′ onto Q′′= Reflection in origin.