wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Points A(1,0), B(5,0), C(7,6) and D(3,6) are joined to form a quadrilateral ABCD. Point B(5,0) is joined with E(5,6) and A(1,0) is joined with F(1,6). Quadrilateral ABEF is completed. BD and AE is joined to intersect at O. Which of the following is correct?


A

Area of triangle ADF = (1/2) × Area of triangle BEC

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

Area of triangle ADF = 1 × Area of triangle BEC

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

Area of triangle ADF = (1/4) × Area of triangle BEC

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

Area of triangle ADF = 2×Area of triangle BEC

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
B

Area of triangle ADF = 1 × Area of triangle BEC


C

Area of triangle ADF = (1/4) × Area of triangle BEC


D

Area of triangle ADF = 2×Area of triangle BEC


Figures on the same base and between the same parallels have equal area. Quad ABCD forms a parallelogram and Quad ABEF forms a rectangle.
Both the figures are on the same base AB and between the same parallels AB and CF.

Thus, area of quad ABCD = Area of quad ABEF and, Area of quad ABOD = Area of quad AOEB
Area of quad ABCD + Area of quad ABED = Area of quad ABEF + Area of quad ABED
Area of Δ ADF = Area of Δ BEC


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon