Points A(5, 3), B(-2, 3) and D(5, -4) are three vertices of a square ABCD. Find the coordinates of the vertex C.
A
(2,4)
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B
(-2,-4)
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C
(2,-4)
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D
(-2,4)
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Solution
The correct option is B (-2,-4) Take a point C on the graph such that ABCD is a square i.e all sides AB, BC, CD and AD are equal. So, the abscissa of C should be equal to the abscissa of B i.e -2 and ordinate of C should be equal to the ordinate of D. i.e -4. Hence, the coordinates of C are (-2, - 4).