Question

Points $A,B,C$ and $D$ are on a line such that $B$ is between $A$ and $C$, and $C$ is between $B$ and $D$. The distance from $A$ to $B$ is $6$ units. The distance from $B$ to $C$ is twice the distance from $A$ to $B$ and the distance from $C$ to $D$ is twice the distance from $B$ to $C$. Calculate the distance, in units from the midpoint of $\overline{BC}$ to the midpoint of $\overline{CD}$?

• A. $18$
• B. $16$
• C. $12$
• D. $9$

Answer 1

Answer: (A)

$18$

Distance from A to B is $6$ units

$\therefore$ Distance from B to C is $2\times 6=12units$

$\therefore$Distance from C to D is $2\times 12units=24units$

$\therefore$ Distance from midpoint of $\overline{BC}$ to midpoint of $\overline{CD}=6units+12units=18units$