Question

Points are to be recognised on X-Y plane to draw graph of equation $2x+3y=12$. So fill the boxes given below and identify points.

Answer 1

Given the equation is $2x+3y=12$

or, $x=\frac{12-3y}{2}$......(1) and $y=\frac{12-2x}{3}$......(2).

Now, for $x=3,6$ respectively we've from (2) we get, $y=2,0$ respectively.

Now for $y=4,6$ respectively we have from (1) we get, $x=0,-3$ respectively.

So the points are $(0,4),(3,2),(6,0),(-3,6)$.