You visited us 1 times! Enjoying our articles? Unlock Full Access!

Average Velocity in 2D Motion

Points I, II ...

Question

Points I, II and III in the following plot respectively correspond to $u_{m p}$ (most probable velocity).

Choose the correct order in increasing order of their most probable velocity.

u_{m p} of N_{2} (300 K); u_{m p} of H_{2} (300 K); u_{m p} of O_{2} (400 K)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

u_{m p} of H_{2} (300 K); u_{m p} of N_{2} (300 K); u_{m p} of O_{2} (400 K)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

u_{m p} of O_{2} (300 K); u_{m p} of N_{2} (300 K); u_{m p} of H_{2} (400 K)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

u_{m p} of N_{2} (300 K); u_{m p} of O_{2} (400 K); u_{m p} of H_{2} (300 K)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $u_{m p} of N_{2} (300 K); u_{m p} of O_{2} (400 K); u_{m p} of H_{2} (300 K)$
$u_{m p} = \sqrt{\frac{2 R T}{M}} \Rightarrow u_{m p} \propto \sqrt{\frac{T}{M}}$
For $N_{2}, O_{2}, H_{2}$
$\sqrt{\frac{300}{28}} < \sqrt{\frac{400}{32}} < \sqrt{\frac{300}{2}}$
$u_{m p} of N_{2} (300 K) < u_{m p} of O_{2} (400 K) < u_{m p} of H_{2} (300 K)$
Hence, option (d) is correct.

Suggest Corrections

Similar questions

f (v)

speed (v)

N_{2} (300 K), O_{2} (400 K), H_{2} (300 K)

1

2

3

v_{m p}

C H_{3} C H_{2} C H O

C H_{3} C H_{2} C H_{2} O H

C H_{3} C H_{2} C H_{3}

A, B

C

(u_{r m s})

(u_{m p})

(u_{a v})

K_{2} C O_{3} (I), M g C O_{3} (I I), C a C O_{3} (I I I), B e C O_{3} (I V)

(i) C H_{3} C H_{2} C H_{2} C H O

(i i) C H_{3} C H_{2} C H_{2} C H_{2} O H

(i i i) C_{2} H_{5} O C_{2} H_{5}

(i v) C H_{3} C H_{2} C H_{2} C H_{3}

Join BYJU'S Learning Program