Polarisibility of halide ions increases in the order:

F^{-}, I^{-}, B r^{-}, C l^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C l^{-}, B r^{-}, I^{-}, F^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I^{-}, B r^{-}, C l^{-}, F^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F^{-}, C l^{-}, B r^{-}, I^{-}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B $F^{-}, C l^{-}, B r^{-}, I^{-}$
Polarisability $α$ Size of anions
This gives us the following order:
Flouride<Chloride<Bromide<Iodide.

Suggest Corrections

Similar questions

Q. The correct order of polarizability is

I^{-}, B r^{-}, C l^{-}, F^{-}

Among halogens, the correct order of amount of energy released in electron gain (electron gain enthalpy ) is
(a) F > Cl > Br > I (b) F < Cl < Br < I (c) F < Cl > Br > I (d) F < Cl < Br < I

Q. For the species

(I^{-}, C l^{-}, B r^{-})

, the increasing order of nucleophilicity in water would be:

Q. Arrange the following bonds according to their average bond energies in descending order:

C - C l, C - B r, C - F, C - I

Q. Increasing oxidising nature of

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

is :

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

.
if true enter 1, else enter 0.

Join BYJU'S Learning Program

Polarisibility of halide ions increases in the order:

The correct option is B F−,Cl−,Br−,I−Polarisability α Size of anionsThis gives us the following order:Flouride<Chloride<Bromide<Iodide.

The correct option is B $F^{-}, C l^{-}, B r^{-}, I^{-}$
Polarisability $α$ Size of anions
This gives us the following order:
Flouride<Chloride<Bromide<Iodide.