Question

Polarising action of $C{d}^{2+}$ on anion is stronger than that of $C{a}^{2+}$ because:

• A. The charges of the ions are same
• B. Their radii are same $(C{a}^{2+}=0.104nm;C{d}^{2+}=0.099nm)$
• C. The $C{a}^{2+}$ ion has a noble-gas electron configuration, and the $C{d}^{2+}$ ion, an 18 electron configuration of its outer shell
• D. All of the above are correct

Answer 1

The correct option is C The $C{a}^{2+}$ ion has a noble-gas electron configuration, and the $C{d}^{2+}$ ion, an 18 electron configuration of its outer shell

Polarising action of $C{d}^{2+}$ on anion is stronger than that of $C{a}^{2+}$ because the $C{a}^{2+}$ ion has a noble-gas electron configuration, and the $C{d}^{2+}$ ion, an 18 electron configuration of its outer shell. A cation with 18 valence electrons has more polarizing power than a cation with 8 valence electrons.