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Polymer

Polypropylene...

Question

Polypropylene can be obtained by polymerisation of :

A

C H_{2} = C H - C H_{3}

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B

C H_{2} = C H_{2}

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C

C H_{4}

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D

C H_{3} - C H_{3}

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Solution

The correct option is A $C H_{2} = C H - C H_{3}$
$n C H_{3} - H C = C H_{2} ⟶ (- C H_{2} - C | H C H_{3} -)_{n} porypropylene$

Hence, polypropylene must have its monomeric unit derived from propylene (3 carbon unit).

Hence the correct option is A.

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Similar questions

Q. Match the column

A, B

C

Reactabts $(A)$	Products $(B)$	Name of the reaction $(C)$
$C H_{3} - C H_{3} + C l_{2}$	$C O_{2} + H_{2} O$	Addition reaction
$C_{2} H_{6} + O_{2}$	$C H_{2} = C H_{2}$	Thermal cracking
$_{n} C H_{2} = C H_{2}$	$C H_{2} = C H_{2} + C H_{4}$	Substitution reactions
$C H_{3} - C H_{2} - C H_{3}$	$C H_{3} - C H_{2} C l + H C l$	Polymerisation
$C H \equiv C H + H_{2}$	$[- C H_{2} - C H_{2} -]_{n}$	Combustion

Q. IUPAC name of given compound:

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H | C H_{3} - C | C H_{3} - C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{2} - C H_{3}

Q. Pick out the correct reactions:

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

Q. The correct order of C - H bond length in

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

C H_{3} - O H | C H - C H_{2} - C H_{2} - O | | C - C H_{3} \to C H_{3} - O H | C H - (C H_{2})_{3} - C H_{3}

.
Given conversion can be achieved by:

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