Population of state B in 2002 is what percent of the total population of State B in all the years together? Rounded off your answer to two digits after decimal.

8.26 %

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7.26 %

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8.32 %

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7.82 %

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None of these

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Solution

The correct option is E None of these
Total population of state B in all the years
$= (50 + 40 + 60 + 70 + 80 + 90 + 100) l a k h s$
$= 490 l a k h s$

Population of state B in 2002 $= 40 l a k h s$
$∴$ required percentage $= \frac{40}{490} \times 100 = 8.16 %$

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Population of state B in 2002 is what percent of the total population of State B in all the years together? Rounded off your answer to two digits after decimal.

The correct option is E None of theseTotal population of state B in all the years =(50+40+60+70+80+90+100) lakhs =490 lakhs Population of state B in 2002 =40 lakhs ∴ required percentage =40490×100=8.16%

The correct option is E None of these
Total population of state B in all the years
$= (50 + 40 + 60 + 70 + 80 + 90 + 100) l a k h s$
$= 490 l a k h s$

Population of state B in 2002 $= 40 l a k h s$
$∴$ required percentage $= \frac{40}{490} \times 100 = 8.16 %$