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German Invasion of the Soviet Union

Position of a...

Question

Position of a particle moving along $x -$ axis is given by $x = 2 t + 4$ . Here $t$ is in seconds and x in metre. Magnitude of displacement (in $m$ ) of particle from $t_{1} = 1 s$ to $t_{2} = 2 s$ .

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Solution

Given,

Position,

$x = 2 t + 4$

Initial position,

$x_{i} = x (t = 1 s) = 2 (1) + 4 = 6 m$

Final position,

$x_{f} = x (t = 2 s) = 2 (2) + 4 = 8 m$

Displacement,

$Δ x = x_{f} - x_{i} = 8 - 6 = 2 m$

Final answer : $2 m$

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