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Standard XII

Physics

Finding Average Velocity

Position of a...

Question

Position of a particle moving along $x -$ axis is given by $x = t^{2} - 6 t + 8$ . Here $t$ is in seconds. Initial position of particle is

10 m

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6 m

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8 m

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3 m

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Solution

The correct option is C $8 m$
Position of particle is given by, $x = t^{2} - 6 t + 8$

Initial position means position at $t = 0$ ,

Putting $t = 0$ ,

We get $x = 8 m$ .

Final answer : (b)

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Finding Average Velocity

Standard XII Physics

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Position of a particle moving along x− axis is given by x=t2−6t+8. Here t is in seconds. Initial position of particle is

The correct option is C 8 mPosition of particle is given by, x=t2−6t+8 Initial position means position at t=0, Putting t=0, We get x=8m. Final answer : (b)

Position of a particle moving along $x -$ axis is given by $x = t^{2} - 6 t + 8$ . Here $t$ is in seconds. Initial position of particle is

The correct option is C $8 m$
Position of particle is given by, $x = t^{2} - 6 t + 8$

Initial position means position at $t = 0$ ,

Putting $t = 0$ ,

We get $x = 8 m$ .

Final answer : (b)