Question

Position of a particle moving in a straight line is given by $x=t^3-6t^2+9t$, where $t$ is measured in second and $x$ is in m. Particle will be at rest at time

• A. $t=3\text{s}$
• B. $t=1\text{s}$
• C. $t=2\text{s}$
• D. Both $\left(1\right)$ & $\left(3\right)$

Answer 1

The correct option is D Both $\left(1\right)$ & $\left(3\right)$

Answer (4)
Velocity of the particle $v=3t^2-12t+9$
Particle will be at rest when $v=0$
$3t^2-12t+9=0$
On solving, $t=1,3$