The correct option is B Period = 3
Group = 16
3216Eimplies that the atomic number of the element ‘E’ is 16 and the mass number is 32.
Electronic configuration of element ‘E’ = 2, 8, 6
Period = Number of shells = 3
Group = Number of valence electrons + 10 = 6 + 10 = 16
Hence, the correct answer is option (b).