Position of the point (1,1) with respect to the circle x2+y2−x+y−1=0 is
Outside the circle
Upon the circle
Inside the circle
can't be told
S1>0,hence point lies outside.
If the middle point of a chord of the circle x2+y2+x−y−1=0 be (1,1), then the length of the chord is
Find the position of the circles x2+y2−2x−6y+9=0 and x2+y2+6x−2y+1=0 with respect to each other.