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Basic Differentiation Rule

Position -tim...

Question

Position -time(x-t) grapg of a particle moving along x-axis is as shown in the figure.The average speed of particle in time interval t=0 to t=10s is

{2 m s}^{- 1}

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\frac{4}{5} {m s}^{- 1}

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{1 m s}^{- 1}

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\frac{5}{4} {m s}^{- 1}

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Solution

The correct option is A ${2 m s}^{- 1}$
Average Speed $(v) = \frac{T o t a l D i s t a n c e}{T o t a l T i m e}$

where, Time = 10 s And, Total Distance $= \frac{1}{2} (4) \times (2 + 10) = 24 m$
$\Rightarrow v = \frac{24}{10} = 2.4 m / s$

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Position -time(x-t) grapg of a particle moving along x-axis is as shown in the figure.The average speed of particle in time interval t=0 to t=10s is

The correct option is A 2ms−1Average Speed (v)=TotalDistanceTotalTimewhere, Time = 10 s And, Total Distance =12(4)×(2+10)=24m⇒v=2410=2.4m/s

The correct option is A ${2 m s}^{- 1}$
Average Speed $(v) = \frac{T o t a l D i s t a n c e}{T o t a l T i m e}$

where, Time = 10 s And, Total Distance $= \frac{1}{2} (4) \times (2 + 10) = 24 m$
$\Rightarrow v = \frac{24}{10} = 2.4 m / s$