Positive and negative point charges of equal magnitude are kept at 0-0- a-2 and 0-0- -a-2 - respectively- The work done by the electric field when another positive point charge is moved from -a- 0-0 to 0- a- 0 is-

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Standard XII

Physics

Potential at a General Point Due to a Dipole

Positive and ...

Question

Positive and negative point charges of equal magnitude are kept at $(0, 0, \frac{a}{2})$ and $(0, 0, \frac{- a}{2})$ , respectively. The work done by the electric field when another positive point charge is moved from $(- a, 0, 0)$ to $(0, a, 0)$ is:

positive

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negative

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zero

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depends on the path connecting the initial and final positions

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Solution

The correct option is D zero
The resultant Electric field due to both charges is radially outward and the movement is perpendicular to the direction of electric field hence the work done is zero.

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Positive and negative point charges of equal magnitude are kept at (0,0,a2) and (0,0,−a2) , respectively. The work done by the electric field when another positive point charge is moved from (−a,0,0) to (0,a,0) is:

The correct option is D zeroThe resultant Electric field due to both charges is radially outward and the movement is perpendicular to the direction of electric field hence the work done is zero.

Positive and negative point charges of equal magnitude are kept at $(0, 0, \frac{a}{2})$ and $(0, 0, \frac{- a}{2})$ , respectively. The work done by the electric field when another positive point charge is moved from $(- a, 0, 0)$ to $(0, a, 0)$ is:

The correct option is D zero
The resultant Electric field due to both charges is radially outward and the movement is perpendicular to the direction of electric field hence the work done is zero.