Positive and negative point charges of equal magnitude are kept at 0-0 a 2 and 0-0 -a 2 - respectively- The work done by the electric field when another positive point charge is moved from -a-0-0 to 0-a-0 is-

The correct option is D zeroRefer to Image #10; #10;Since point( a,0,0) and (0,a,0) lies in equatorial plane of #10;the two charge work done is zero. ...

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Standard XII

Physics

Electric Field

Positive and ...

Question

Positive and negative point charges of equal magnitude are kept at $(0, 0 \frac{a}{2})$ and $(0, 0 \frac{- a}{2})$ , respectively. The work done by the electric field when another positive point charge is moved from $(- a, 0, 0)$ to $(0, a, 0)$ is:

positive

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negative

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zero

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depends on the path connecting the initial and final positions

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Solution

The correct option is D zero
Refer to Image

Since point(-a,0,0) and (0,a,0) lies in equatorial plane of the two charge work done is zero.

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Positive and negative point charges of equal magnitude are kept at (0,0a2) and (0,0−a2), respectively. The work done by the electric field when another positive point charge is moved from (−a,0,0) to (0,a,0) is:

The correct option is D zeroRefer to Image Since point(-a,0,0) and (0,a,0) lies in equatorial plane of the two charge work done is zero.

Positive and negative point charges of equal magnitude are kept at $(0, 0 \frac{a}{2})$ and $(0, 0 \frac{- a}{2})$ , respectively. The work done by the electric field when another positive point charge is moved from $(- a, 0, 0)$ to $(0, a, 0)$ is:

The correct option is D zero
Refer to Image

Since point(-a,0,0) and (0,a,0) lies in equatorial plane of the two charge work done is zero.