Possible polynomial expression for the given volume of cuboid $12 y^{2} + 8 y - 20$ is

4 (3 y + 5) (y - 1)

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4 (3 y - 4) (y - 2)

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4 (3 y + 4) (y + 3)

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None of the above

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Solution

The correct option is A $4 (3 y + 5) (y - 1)$
Given volume of cuboid $=$ $12 y^{2} + 8 y - 20$
$= 4 (3 y^{2} + 2 y - 5)$
$= 4 (3 y^{2} + 5 y - 3 y - 5)$
$= 4 [y (3 y + 5) - 1 (3 y + 5)]$
$= 4 (3 y + 5) (y - 1)$
Then dimensions of cuboid are $4, (3 y + 5),$ and $(y - 1)$ .

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By Substitution method

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